x^2+48x-1260=0

Solution for x^2+48x-1260=0 equation:

x^2+48x-1260=0

a = 1; b = 48; c = -1260;
Δ = b2-4ac
Δ = 482-4·1·(-1260)
Δ = 7344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7344}=\sqrt{144*51}=\sqrt{144}*\sqrt{51}=12\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-12\sqrt{51}}{2*1}=\frac{-48-12\sqrt{51}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+12\sqrt{51}}{2*1}=\frac{-48+12\sqrt{51}}{2}
$